Re: Urgent doubt.

From: Beata Winnicka <bfatyga@slab.extreme.indiana.edu>
Date: Mon, 1 May 95 09:15:11 -0500
To: "Arun P. Muthukumar" <arunp@engr.uky.edu>
Subject: Re: Urgent doubt.
Cc: sage-bugs@rainier.extreme.indiana.edu
Sender: owner-sage-bugs@extreme.indiana.edu

> I have a doubt regarding forming a SgExpression.
> 

> Assume that I use 'gets(char *)' to get an expression from
> the user. So the program asks something like:
> 

>     Enter Expression:
> 

> for which the user would enter     n1 * n2 / n3
> 

> Now, how can I make this as an instance of (SgExpression *)  

> example: SgExpression *exp;
> 

> 	  I want 'exp' to be (n1 * n2 / n3)
> 

>  Is there a direct way by which I can do this. I tried several 

> methods, but nothing seems to work fine.
> 

>  An early reply would be very much appreciated.
> 

>    thanks  arun 

> 


No, there is no direct way to do what you want. Basically , you would have
to write your own expression scanner and parser.   --Beata